Optimal. Leaf size=149 \[ -\frac {35 d^3 \sqrt {d^2-e^2 x^2}}{8 e}-\frac {35 d^2 (d+e x) \sqrt {d^2-e^2 x^2}}{24 e}-\frac {7 d (d+e x)^2 \sqrt {d^2-e^2 x^2}}{12 e}-\frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{4 e}+\frac {35 d^4 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{8 e} \]
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Rubi [A]
time = 0.04, antiderivative size = 149, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {685, 655, 223,
209} \begin {gather*} \frac {35 d^4 \text {ArcTan}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{8 e}-\frac {35 d^2 (d+e x) \sqrt {d^2-e^2 x^2}}{24 e}-\frac {7 d (d+e x)^2 \sqrt {d^2-e^2 x^2}}{12 e}-\frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{4 e}-\frac {35 d^3 \sqrt {d^2-e^2 x^2}}{8 e} \end {gather*}
Antiderivative was successfully verified.
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Rule 209
Rule 223
Rule 655
Rule 685
Rubi steps
\begin {align*} \int \frac {(d+e x)^4}{\sqrt {d^2-e^2 x^2}} \, dx &=-\frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{4 e}+\frac {1}{4} (7 d) \int \frac {(d+e x)^3}{\sqrt {d^2-e^2 x^2}} \, dx\\ &=-\frac {7 d (d+e x)^2 \sqrt {d^2-e^2 x^2}}{12 e}-\frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{4 e}+\frac {1}{12} \left (35 d^2\right ) \int \frac {(d+e x)^2}{\sqrt {d^2-e^2 x^2}} \, dx\\ &=-\frac {35 d^2 (d+e x) \sqrt {d^2-e^2 x^2}}{24 e}-\frac {7 d (d+e x)^2 \sqrt {d^2-e^2 x^2}}{12 e}-\frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{4 e}+\frac {1}{8} \left (35 d^3\right ) \int \frac {d+e x}{\sqrt {d^2-e^2 x^2}} \, dx\\ &=-\frac {35 d^3 \sqrt {d^2-e^2 x^2}}{8 e}-\frac {35 d^2 (d+e x) \sqrt {d^2-e^2 x^2}}{24 e}-\frac {7 d (d+e x)^2 \sqrt {d^2-e^2 x^2}}{12 e}-\frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{4 e}+\frac {1}{8} \left (35 d^4\right ) \int \frac {1}{\sqrt {d^2-e^2 x^2}} \, dx\\ &=-\frac {35 d^3 \sqrt {d^2-e^2 x^2}}{8 e}-\frac {35 d^2 (d+e x) \sqrt {d^2-e^2 x^2}}{24 e}-\frac {7 d (d+e x)^2 \sqrt {d^2-e^2 x^2}}{12 e}-\frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{4 e}+\frac {1}{8} \left (35 d^4\right ) \text {Subst}\left (\int \frac {1}{1+e^2 x^2} \, dx,x,\frac {x}{\sqrt {d^2-e^2 x^2}}\right )\\ &=-\frac {35 d^3 \sqrt {d^2-e^2 x^2}}{8 e}-\frac {35 d^2 (d+e x) \sqrt {d^2-e^2 x^2}}{24 e}-\frac {7 d (d+e x)^2 \sqrt {d^2-e^2 x^2}}{12 e}-\frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{4 e}+\frac {35 d^4 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{8 e}\\ \end {align*}
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Mathematica [A]
time = 0.29, size = 100, normalized size = 0.67 \begin {gather*} \frac {\sqrt {d^2-e^2 x^2} \left (-160 d^3-81 d^2 e x-32 d e^2 x^2-6 e^3 x^3\right )}{24 e}-\frac {35 d^4 \log \left (-\sqrt {-e^2} x+\sqrt {d^2-e^2 x^2}\right )}{8 \sqrt {-e^2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(260\) vs.
\(2(129)=258\).
time = 0.47, size = 261, normalized size = 1.75
method | result | size |
risch | \(-\frac {\left (6 e^{3} x^{3}+32 d \,e^{2} x^{2}+81 d^{2} e x +160 d^{3}\right ) \sqrt {-e^{2} x^{2}+d^{2}}}{24 e}+\frac {35 d^{4} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{8 \sqrt {e^{2}}}\) | \(83\) |
default | \(e^{4} \left (-\frac {x^{3} \sqrt {-e^{2} x^{2}+d^{2}}}{4 e^{2}}+\frac {3 d^{2} \left (-\frac {x \sqrt {-e^{2} x^{2}+d^{2}}}{2 e^{2}}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{2 e^{2} \sqrt {e^{2}}}\right )}{4 e^{2}}\right )+4 d \,e^{3} \left (-\frac {x^{2} \sqrt {-e^{2} x^{2}+d^{2}}}{3 e^{2}}-\frac {2 d^{2} \sqrt {-e^{2} x^{2}+d^{2}}}{3 e^{4}}\right )+6 d^{2} e^{2} \left (-\frac {x \sqrt {-e^{2} x^{2}+d^{2}}}{2 e^{2}}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{2 e^{2} \sqrt {e^{2}}}\right )-\frac {4 d^{3} \sqrt {-e^{2} x^{2}+d^{2}}}{e}+\frac {d^{4} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{\sqrt {e^{2}}}\) | \(261\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.51, size = 96, normalized size = 0.64 \begin {gather*} \frac {35}{8} \, d^{4} \arcsin \left (\frac {x e}{d}\right ) e^{\left (-1\right )} - \frac {1}{4} \, \sqrt {-x^{2} e^{2} + d^{2}} x^{3} e^{2} - \frac {4}{3} \, \sqrt {-x^{2} e^{2} + d^{2}} d x^{2} e - \frac {20}{3} \, \sqrt {-x^{2} e^{2} + d^{2}} d^{3} e^{\left (-1\right )} - \frac {27}{8} \, \sqrt {-x^{2} e^{2} + d^{2}} d^{2} x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.70, size = 78, normalized size = 0.52 \begin {gather*} -\frac {1}{24} \, {\left (210 \, d^{4} \arctan \left (-\frac {{\left (d - \sqrt {-x^{2} e^{2} + d^{2}}\right )} e^{\left (-1\right )}}{x}\right ) + {\left (6 \, x^{3} e^{3} + 32 \, d x^{2} e^{2} + 81 \, d^{2} x e + 160 \, d^{3}\right )} \sqrt {-x^{2} e^{2} + d^{2}}\right )} e^{\left (-1\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 5.28, size = 546, normalized size = 3.66 \begin {gather*} d^{4} \left (\begin {cases} \frac {\sqrt {\frac {d^{2}}{e^{2}}} \operatorname {asin}{\left (x \sqrt {\frac {e^{2}}{d^{2}}} \right )}}{\sqrt {d^{2}}} & \text {for}\: d^{2} > 0 \wedge e^{2} > 0 \\\frac {\sqrt {- \frac {d^{2}}{e^{2}}} \operatorname {asinh}{\left (x \sqrt {- \frac {e^{2}}{d^{2}}} \right )}}{\sqrt {d^{2}}} & \text {for}\: d^{2} > 0 \wedge e^{2} < 0 \\\frac {\sqrt {\frac {d^{2}}{e^{2}}} \operatorname {acosh}{\left (x \sqrt {\frac {e^{2}}{d^{2}}} \right )}}{\sqrt {- d^{2}}} & \text {for}\: d^{2} < 0 \wedge e^{2} < 0 \end {cases}\right ) + 4 d^{3} e \left (\begin {cases} \frac {x^{2}}{2 \sqrt {d^{2}}} & \text {for}\: e^{2} = 0 \\- \frac {\sqrt {d^{2} - e^{2} x^{2}}}{e^{2}} & \text {otherwise} \end {cases}\right ) + 6 d^{2} e^{2} \left (\begin {cases} - \frac {i d^{2} \operatorname {acosh}{\left (\frac {e x}{d} \right )}}{2 e^{3}} + \frac {i d x}{2 e^{2} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}}} - \frac {i x^{3}}{2 d \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}}} & \text {for}\: \left |{\frac {e^{2} x^{2}}{d^{2}}}\right | > 1 \\\frac {d^{2} \operatorname {asin}{\left (\frac {e x}{d} \right )}}{2 e^{3}} - \frac {d x \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}}}{2 e^{2}} & \text {otherwise} \end {cases}\right ) + 4 d e^{3} \left (\begin {cases} - \frac {2 d^{2} \sqrt {d^{2} - e^{2} x^{2}}}{3 e^{4}} - \frac {x^{2} \sqrt {d^{2} - e^{2} x^{2}}}{3 e^{2}} & \text {for}\: e \neq 0 \\\frac {x^{4}}{4 \sqrt {d^{2}}} & \text {otherwise} \end {cases}\right ) + e^{4} \left (\begin {cases} - \frac {3 i d^{4} \operatorname {acosh}{\left (\frac {e x}{d} \right )}}{8 e^{5}} + \frac {3 i d^{3} x}{8 e^{4} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}}} - \frac {i d x^{3}}{8 e^{2} \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}}} - \frac {i x^{5}}{4 d \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}}} & \text {for}\: \left |{\frac {e^{2} x^{2}}{d^{2}}}\right | > 1 \\\frac {3 d^{4} \operatorname {asin}{\left (\frac {e x}{d} \right )}}{8 e^{5}} - \frac {3 d^{3} x}{8 e^{4} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}}} + \frac {d x^{3}}{8 e^{2} \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}}} + \frac {x^{5}}{4 d \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}}} & \text {otherwise} \end {cases}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 2.12, size = 63, normalized size = 0.42 \begin {gather*} \frac {35}{8} \, d^{4} \arcsin \left (\frac {x e}{d}\right ) e^{\left (-1\right )} \mathrm {sgn}\left (d\right ) - \frac {1}{24} \, {\left (160 \, d^{3} e^{\left (-1\right )} + {\left (81 \, d^{2} + 2 \, {\left (3 \, x e^{2} + 16 \, d e\right )} x\right )} x\right )} \sqrt {-x^{2} e^{2} + d^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (d+e\,x\right )}^4}{\sqrt {d^2-e^2\,x^2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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